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0=x^2-15x-25
We move all terms to the left:
0-(x^2-15x-25)=0
We add all the numbers together, and all the variables
-(x^2-15x-25)=0
We get rid of parentheses
-x^2+15x+25=0
We add all the numbers together, and all the variables
-1x^2+15x+25=0
a = -1; b = 15; c = +25;
Δ = b2-4ac
Δ = 152-4·(-1)·25
Δ = 325
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{325}=\sqrt{25*13}=\sqrt{25}*\sqrt{13}=5\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-5\sqrt{13}}{2*-1}=\frac{-15-5\sqrt{13}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+5\sqrt{13}}{2*-1}=\frac{-15+5\sqrt{13}}{-2} $
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